URI - BEECROWD - BEE 1038 | Snake Solution in C,C++,Python

URI - BEECROWD - BEE Online Judge Solution  1038 | Snake - URI - BEECROWD - BEE 1038 Solution in C,C++,Python 

Using the following table, write a program that reads a code and the amount of an item. After, print the value to pay. This is a very simple program with the only intention of practice of selection commands.

Input

The input file contains two integer numbers X and Y. X is the product code and Y is the quantity of this item according to the above table.

Output

The output must be a message "Total: R$ " followed by the total value to be paid, with 2 digits after the decimal point.

Input Sample	Output Sample
3 2	Total: R$ 10.00

4 3	Total: R$ 6.00

2 3	Total: R$ 13.50

URI Online Judge Solution  1038 | Snake - URI 1038 Solution in C,C++,Python :

  URI Problem 1038 Solution in C :   

URI Online Judge 1038 Solve  in C :

#include<stdio.h>
int main()
{
    int X, Y;
    float price = 0;

    scanf("%d %d", &X, &Y);
    if (X == 1)
    {
        price  = (float) (4.00 * Y);
    }
    else if (X == 2)
    {
        price  = (float) (4.50 * Y);
    }
    else if (X == 3)
    {
        price  = (float) (5.00 * Y);
    }
    else if (X == 4)
    {
        price  = (float) (2.00 * Y);
    }
    else if (X == 5)
    {
        price  = (float) (1.50 * Y);
    }

    printf("Total: R$ %.2f\n",price);

}

  URI Problem 1038 Solution in C ++:

URI Online Judge 1038 Solve  in C++ :

#include<bits/stdc++.h>
using namespace std;

int main(){
    int x,y;
    double x1=4.00,x2=4.50,x3=5.00,x4=2.00,x5=1.50,ans=0;

    cin>>x>>y;
    if(x==1){
        ans=x1*y;
    }else if(x==2){
        ans=x2*y;
    }else if(x==3){
        ans=x3*y;
    }else if(x==4){
        ans=x4*y;
    }else if(x==5){
        ans=x5*y;
    }
    cout<<fixed;
    cout<<setprecision(2)<<"Total: R$ "<<ans<<endl;

return 0;
    
}

  URI Problem 1038 Solution in Python:

URI Online Judge 1038 Solve  in Python  :

X,Y=list(map(int,input().split()))
if(X == 1):
    price  = (float) (4.00 * Y)
elif(X == 2):
    price  = (float) (4.50 * Y)
elif(X == 3):
    price  = (float) (5.00 * Y)
elif (X == 4):
    price  = (float) (2.00 * Y);
elif (X == 5):
    price  = (float) (1.50 * Y)
print(f"Total: R$ {price:.2f}")

URI Online Judge 1038 Solve  in Python  :                                                     Another Solution

X,Y = map(int,input().split())
Item = {1:4.0,2:4.5,3:5.0,4:2.0,5:1.5}
X = float(Item[X])*Y
print(f"Total: R$ {X:.2f}")

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