URI - BEECROWD - BEE 1065 - Even Between Five Numbers Solution in C,C++,Python

URI - BEECROWD - BEE 1065 - Even Between Five Numbers Solution in C,C++,Python |  URI - BEECROWD - BEE Online Judge Solution 1065 - Even Between Five Numbers

Make a program that reads five integer values. Count how many of these values ​​are even and  print this information like the following example.

Input

The input will be 5 integer values.

Output

Print a message like the following example with all letters in lowercase, indicating how many even numbers were typed.

Input Sample	Output Sample
7 -5 6 -4 12	3 valores pares

 URI - BEECROWD - BEE 1065 - Even Between Five Numbers Solution in C,C++,Python |  URI - BEECROWD - BEE Online Judge Solution 1065 - Even Between Five Numbers:

                                        Demonstration:

Even numbers are those numbers that can be divided into two equal groups or pairs and are exactly divisible by 2.

Here we apply a range-based for loop which provides all the integers available in the input interval.

After this, a check condition for even numbers is applied to filter all the odd numbers and increment the count variable. 

Finally, print the result.

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

   URI - BEECROWD - BEE Problem 1065 Solution in C :   

URI - BEECROWD - BEE Online Judge 1065 Solve  in C :

#include <stdio.h>
 
int main()
{
    int i,num,count=0;
    for(i=1;i<=5;i++){
        scanf("%d",&num);
        if(num%2==0){
          count++;
        }
    }
    printf("%d valores pares\n",count);
    return 0;
}

 URI - BEECROWD - BEE Problem 1065 Solution in C ++:

URI - BEECROWD - BEE Online Judge 1065 Solve  in C++ :

#include <bits/stdc++.h>
using namespace std;
 
int main()
{
    int i,num,count=0;
    for(i=1;i<=5;i++){
        cin >> num;
        if(num%2==0){
          count++;
        }
    }
    cout<<count<<" valores pares"<<endl;
    return 0;
}

 URI-BEECROWD-BEE Problem 1065 Solution in Python:

URI - BEECROWD - BEE Online Judge 1065 Solve  in Python  :

count=0
for i in range(5):
    n = float(input())
    if(n%2==0):
        count=count+1
print(f"{count} valores pares")

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