URI / BEE CROWD 1075 - Remaining 2 Solution in C,C++,Python | URI - BEECROWD - BEE 1075 Solution in C,C++,Python

                                                                                            beecrowd | 1075

Remaining 2

Adapted by Neilor Tonin, URI  Brazil

                                                                                             Timelimit: 1

Read an integer N. Print all numbers between 1 and 10000, which divided by N will give the rest = 2.

Input

The input is an integer N (N < 10000)

Output

Print all numbers between 1 and 10000, which divided by n will give the rest = 2, one per line.

Input Sample	Output Sample
13	2 15 28 41 ...

URI / BEE CROWD 1075 - Remaining 2 Solution in C,C++,Python | URI - BEECROWD - BEE 1075 Solution in C,C++,Python

                                     Demonstration:

Here we apply a range-based for loop which provides all the integers available in the input interval.

After this, checking the condition for this problem which divided by N will give the rest = 2

Finally, print the result. 

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

  URI / BEE 1075 Solution in C :   

URI / BEECROWD Online Judge 1075 Solve  in C :

#include<stdio.h>

int main()
{
    int i,n;
    scanf("%d",&n);
    for(i=1;i<=10000;i++){
        if(i%n==2){
            printf("%d\n",i);
        }
    }
}

  URI / BEE 1075 Solution in C++ :   

URI / BEECROWD Online Judge 1075 Solve  in C++ :

#include <iostream>

using namespace std;

int main(){
    int n;
    cin >> n;
    
    for(int i = 1; i < 10000; i++){
            if(i%n == 2)
            cout << i << "\n";
    }
    
    return 0;
}

  URI / BEE 1075 Solution in Python :   

URI / BEECROWD Online Judge 1075 Solve  in Python :

n=int(input())
for i in range(1,10000):
    if(i%n==2):
        print(i)

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