URI / BEE CROWD 1145 - Logical Sequence 2 - Solution in C,C++,Python | URI - BEECROWD - BEE 1145 Solution in C,C++,Python

                                                                                             beecrowd | 1145

Logical Sequence 2

Adapted by Neilor Tonin, URI  Brazil

                                                                                             Timelimit: 1

URI / BEE CROWD 1145 - Logical Sequence 2 - Solution in C,C++,Python | URI - BEECROWD - BEE 1145 Solution in C,C++,Python:

Write a program that reads an integer N. N * 2 lines must be printed by this program according to the example below. For numbers with more than 6 digits, all digits must be printed (no cientific notation allowed).

Input

The input file contains an integer N (1 < N < 1000).

Output

Print the output according to the given example.

Input Sample	Output Sample
5	1 1 1 1 2 2 2 4 8 2 5 9 3 9 27 3 10 28 4 16 64 4 17 65 5 25 125 5 26 126

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

  URI / BEE 1145 Solution in C :   

URI / BEECROWD Online Judge 1145 Solve  in C :

#include <stdio.h>
int main()
{
    int n,a,b,i,j,k,l,m=1;
    scanf("%d %d",&a,&n);
    k=n/a;
    l=a;
    for(i=1;i<=k;i++)
	{
		printf("%d",m);
		for(j=m+1;j<=l;j++)
		{
			printf(" %d",j);
		}
		printf("\n");
		m=m+a;
		l=l+a;
	}

    return 0;
}

  URI / BEE 1145 Solution in C++ :   

URI / BEECROWD Online Judge 1145 Solve  in C++ :

#include <iostream>

using namespace std;

int main(){
    
    int x,y;
    
    cin >> x;
    cin >> y;
    
    int n = 1;
    
    for(int i = 1; i <= y; i++){
            if(n == x) {
                 cout << i << "\n";
                 n = 1;
            }
            else{
            cout << i << " ";
            n++;
            }
    }
    return 0;
}

  URI / BEE 1145 Solution in Python :   

URI / BEECROWD Online Judge 1145 Solve  in Python :

n1,n2 = list(map(int,input().split()))
cont = 1
for i in range(1,(int((n2/n1))+1)):
    r = ""
    for y in range(n1):
        r += str(cont) + " "
        cont += 1
    print(r[:-1])

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