URI - BEECROWD - BEE 1011 | Sphere Solution in C,C++,Python

URI - BEECROWD - BEE Online Judge Solution  1011 | Sphere - URI - BEECROWD - BEE Problem 1011 Solution in C,C++,Python 

Make a program that calculates and shows the volume of a sphere being provided the value of its radius (R) . The formula to calculate the volume is: (4/3) * pi * R3. Consider (assign) for pi the value 3.14159.

Tip: Use (4/3.0) or (4.0/3) in your formula, because some languages (including C++) assume that the division's result between two integers is another integer. :)

Input

The input contains a value of floating point (double precision).

Output

The output must be a message "VOLUME" like the following example with a space before and after the equal signal. The value must be presented with 3 digits after the decimal point.

Input Samples	Output Samples
3	VOLUME = 113.097

15	VOLUME = 14137.155

1523	VOLUME = 14797486501.627

URI Online Judge Solution  1011 | Sphere - URI Problem 1011 Solution in C,C++,Python ::

  URI Problem 1011 Solution in C :   

URI Online Judge 1011 Solve in C :                                                                        #include <stdio.h>     #include <math.h>     int main()     {          int a;          scanf("%i", &a);          printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);          return 0;       }

  URI Problem 1011 Solution in C ++:

URI Online Judge 1011 Solve  in C++ :    #include<bits/stdc++.h>     using namespace std;     int main()     {         int R;         double res;         cin>>R;         res=(4.0/3*3.14159*R*R*R);         cout<<fixed;         cout<<setprecision(3)<<"VOLUME = "<<res<<endl;             return 0;      }

  URI Problem 1011 Solution in Python:

URI Online Judge 1011 Solve in Python :                                                                                                     raio = int(input())     pi = 3.14159     volume = float(4.0 * pi * (raio* raio * raio) / 3)     print(f'VOLUME = {volume:.3f}')

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