URI - BEECROWD - BEE 1012 | Area Solution in C,C++,Python

URI - BEECROWD - BEE Online Judge Solution  1012 | Area - URI - BEECROWD - BEE Problem 1012 Solution in C,C++,Python 

Make a program that reads three floating point values: A, B and C. Then, calculate and show:
a) the area of the rectangled triangle that has base A and height C.
b) the area of the radius's circle C. (pi = 3.14159)
c) the area of the trapezium which has A and B by base, and C by height.
d) the area of ​​the square that has side B.
e) the area of the rectangle that has sides A and B.

Input

The input file contains three double values with one digit after the decimal point.

Output

The output file must contain 5 lines of data. Each line corresponds to one of the areas described above, always with a corresponding message (in Portuguese) and one space between the two points and the value. The value calculated must be presented with 3 digits after the decimal point.

Input Samples	Output Samples
3.0 4.0 5.2	TRIANGULO: 7.800 CIRCULO: 84.949 TRAPEZIO: 18.200 QUADRADO: 16.000 RETANGULO: 12.000

12.7 10.4 15.2

TRIANGULO: 96.520 CIRCULO: 725.833 TRAPEZIO: 175.560 QUADRADO: 108.160 RETANGULO: 132.080

URI Online Judge Solution  1012 | Area - URI Problem 1012 Solution in C,C++,Python ::

  URI Problem 1012 Solution in C :   

URI Online Judge 1012 Solve in C :                                                                        #include <stdio.h>     int main()     {      double a, b, c;      scanf("%lf %lf %lf", &a, &b, &c);      printf("TRIANGULO: %.3lf\n", (a * c) / 2);      printf("CIRCULO: %.3lf\n", c * c * 3.14159);      printf("TRAPEZIO: %.3lf\n", ((a + b) / 2) * c);      printf("QUADRADO: %.3lf\n", b * b);      printf("RETANGULO: %.3lf\n", a * b);      return 0;     }

  URI Problem 1012 Solution in C ++:

URI Online Judge 1012 Solve  in C++ :  #include<bits/stdc++.h>   using namespace std;   int main(){     double a,b,c;     double pi=3.14159,tri,cri,tra,qua,ret;     cin>>a>>b>>c;     tri =0.5*a*c;     cri =pi*(c*c);     tra=(a+b)/2*c;     qua=b*b;     ret=a*b;     cout<<fixed;     cout<<setprecision(3)<<"TRIANGULO: "<<tri<<endl;           cout<<setprecision(3)<<"CIRCULO: "<<cri<<endl;     cout<<setprecision(3)<<"TRAPEZIO: "<<tra<<endl;     cout<<setprecision(3)<<"QUADRADO: "<<qua<<endl;     cout<<setprecision(3)<<"RETANGULO: "<<ret<<endl;     return 0;   }

  URI Problem 1012 Solution in Python:

URI Online Judge 1012 Solve in Python :                                                                                                     a,b,c = list(map(float,input().split()))     triangle=0.5*a*c     circle=3.14159*c*c     trapezium=(a+b)/2.0*c     square=b*b     rectangle=a*b     print("TRIANGULO: %.3lf"%triangle)     print("CIRCULO: %.3f"%circle)     print("TRAPEZIO: %.3f"%trapezium)     print("QUADRADO: %.3f"%square)     print("RETANGULO: %.3f"%rectangle)

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