URI - BEECROWD - BEE 1036 | Bhaskaras Formula Solution in C,C++,Python

URI - BEECROWD - BEE Online Judge Solution  1036 | Bhaskara's Formula - URI - BEECROWD - BEE 1036 Solution in C,C++,Python

Read 3 floating-point numbers. After, print the roots of bhaskara’s formula. If it's impossible to calculate the roots because a division by zero or a square root of a negative number, presents the message “Impossivel calcular”.

Input

Read 3 floating-point numbers (double) A, B and C.

Output

Print the result with 5 digits after the decimal point or the message if it is impossible to calculate.

Input Samples	Output Samples
10.0 20.1 5.1	R1 = -0.29788 R2 = -1.71212

0.0 20.0 5.0

Impossivel calcular

10.3 203.0 5.0

R1 = -0.02466 R2 = -19.68408

URI Online Judge Solution  1036 | Bhaskaras Formula - URI 1036 Solution in C,C++,Python:

  URI Problem 1036 Solution in C :   

URI Online Judge 1036 Solve  in C :

#include<bits/stdc++.h>
#include<math.h>
using namespace std;

int main(){
    double a,b,c,t,R1,R2;
    cin>>a>>b>>c;

    if(((b*b)-4*a*c)<0 ||a==0){
        cout<<"Impossivel calcular"<<endl;
    }else{
         t=sqrt((b*b)-4*a*c);
         R1=((-b + t) / (2 * a));
         R2=((-b - t) / (2 * a));
         cout<<fixed;
         cout<<setprecision(5)<<"R1 = "<<R1<<endl;
         cout<<setprecision(5)<<"R2 = "<<R2<<endl;
    }
    return 0;
}

  URI Problem 1036 Solution in C ++:

URI Online Judge 1036 Solve  in C++ :

#include<stdio.h>
#include <math.h>

int main()
{
 double a, b, c, t;
 scanf("%lf %lf %lf", &a, &b, &c);

 if(((b * b) - 4 * a * c) < 0 || a == 0){
     printf("Impossivel calcular\n");
 }
 else{
  t = sqrt((b * b) - 4 * a * c);
  printf("R1 = %.5lf\nR2 = %.5lf\n", ((-b + t) / (2 * a)), ((-b - t) / (2 * a)));
    }
 return 0;
}

  URI Problem 1036 Solution in Python:

URI Online Judge 1036 Solve  in Python 3.8+ :

import math
A,B,C = map(float,input().split())
D = (B**2)-(4*A*C)
if(D <0 or A==0):
    print("Impossivel calcular")
else:
    D=math.sqrt(D)
    R1 = (-B+D)/(2*A)
    R2 = (-B-D)/(2*A)
    print(f'R1 = {R1:0.5f}\nR2 = {R2:0.5f}')

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