# URI - BEECROWD - BEE 1035 | Selection Test Solution in C,C++,Python

## URI - BEECROWD - BEE Online Judge Solution  1035 | Selection Test 1 - URI - BEECROWD - BEE 1035 Solution in C,C++,Python

Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

## Input

Four integer numbers A, B, C and D.

## Output

Show the corresponding message after the validation of the values​​.

 Input Sample Output Sample 5 6 7 8 Valores nao aceitos
 2 3 2 6 Valores aceitos

### URI Online Judge Solution  1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python:

URI Problem 1035 Solution in C :

 URI Online Judge 1035 Solve  in C :
```#include <stdio.h>

int main()
{
int a, b, c, d;
scanf("%d %d %d %d", &a, &b, &c, &d);

if((b > c) && (d > a) && (c + d > a + b) && c > 0 && d > 0 && (a % 2 == 0))
printf("Valores aceitos\n");
else
printf("Valores nao aceitos\n");

return 0;
}```

### 3 Responses to URI - BEECROWD - BEE 1035 | Selection Test Solution in C,C++,Python

1. Thank You!
Best URI Online Judge Solution Site...

2. if((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0)) . There is a problem at this line, you take c>0 && c>0 , it should be c>0&&d>0 or (c&&d)>0

3. yes ,it's just a typing mistake. Thanks for mentioning. I updated the code,check now.