URI Online Judge Solution 1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python

URI Online Judge Solution  1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python

Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

Input

Four integer numbers A, B, C and D.

Output

Show the corresponding message after the validation of the values​​.

Input SampleOutput Sample

5 6 7 8

Valores nao aceitos

2 3 2 6

Valores aceitos

URI Online Judge Solution  1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python:

  URI Problem 1035 Solution in C :   

  URI Online Judge 1035 Solve  in C :                                                                             
#include <stdio.h>

int main()
{
 int a, b, c, d;
 scanf("%d %d %d %d", &a, &b, &c, &d);

 if((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0))
        printf("Valores aceitos\n");
 else
        printf("Valores nao aceitos\n");

 return 0;
}

1 Response to URI Online Judge Solution 1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python

  1. Thank You!
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