URI - BEECROWD - BEE 1035 | Selection Test Solution in C,C++,Python

URI - BEECROWD - BEE Online Judge Solution  1035 | Selection Test 1 - URI - BEECROWD - BEE 1035 Solution in C,C++,Python

Read 4 integer values A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

Input

Four integer numbers A, B, C and D.

Output

Show the corresponding message after the validation of the values​​.

Input Sample	Output Sample
5 6 7 8	Valores nao aceitos

2 3 2 6

Valores aceitos

URI Online Judge Solution  1035 | Selection Test 1 - URI 1035 Solution in C,C++,Python:

  URI Problem 1035 Solution in C :   

URI Online Judge 1035 Solve  in C :

#include <stdio.h>

int main()
{
 int a, b, c, d;
 scanf("%d %d %d %d", &a, &b, &c, &d);

 if((b > c) && (d > a) && (c + d > a + b) && c > 0 && d > 0 && (a % 2 == 0))
        printf("Valores aceitos\n");
 else
        printf("Valores nao aceitos\n");

 return 0;
}

  URI Problem 1035 Solution in C ++:

URI Online Judge 1035 Solve  in C++ :

#include<bits/stdc++.h>
using namespace std;

int main(){
    int a,b,c,d;

    cin>>a>>b>>c>>d;

    if((b>c)&&(d>a)&&(c+d>a+b)&&c>0&&d>0&&(a%2==0)){
        cout<<"Valores aceitos"<<endl;
    }else{
        cout<<"Valores nao aceitos"<<endl;
    }
  return 0;
}

  URI Problem 1035 Solution in Python:

URI Online Judge 1035 Solve  in Python :

a,b,c,d = map(int,input().split())

if b>c and d>a and (c+d) > (a+b) and c>0 and d>0 and a%2 ==0:
	print( "Valores aceitos")
else:
	print("Valores nao aceitos")

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