URI / BEE CROWD 1095 - Sequence IJ 1 Solution in C,C++,Python | URI - BEECROWD - BEE 1095 Solution in C,C++,Python

                                                                                            beecrowd | 1095

Sequence IJ 1

Adapted by Neilor Tonin, URI  Brazil

                                                                                             Timelimit: 1

URI / BEE CROWD 1095 - Sequence IJ 1 Solution in C,C++,Python | URI - BEECROWD - BEE 1095 Solution in C,C++,Python:

Make a program that prints the sequence like the following example.

Input

This problem doesn't have input.

Output

Print the sequence like the example below.

Input Sample	Output Sample
	I=1 J=60 I=4 J=55 I=7 J=50 ... I=? J=0

                                                          Demonstration:

This program does not take user inputs . Then check the conditions for each test case contains two integer number i and j .Then calculating the sequence by using conditional loop.

Start with i =1 and j =60 . For every iteration, increment i by 3 and decrement by 4.

Finally print the result.

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

  URI / BEE 1095 Solution in C :   

URI / BEECROWD Online Judge 1095 Solve  in C :

#include<stdio.h>

int main()
{
    int i,j;
    for(i=1,j=60;i<15,j>=0;i+=3,j-=5){

            printf("I=%d J=%d\n",i,j);
        }

}

  URI / BEE 1095 Solution in C++ :   

URI / BEECROWD Online Judge 1095 Solve  in C++ :

#include <iostream>

using namespace std;

int main(){
    int i = 1;
    for(int j = 60; j >= 0; j--){
            cout << "I=" << i << " " << "J=" << j << "\n";
            i += 3;
            j -= 4;
    }
    return 0;
}

  URI / BEE 1095 Solution in Python :   

URI / BEECROWD Online Judge 1095 Solve  in Python :

i = 1
j = 60

while j >= 0:
    print(f'I={i} J={j}')
    i = i + 3
    j = j - 5

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