URI / BEE CROWD 1096 - Sequence IJ 2 Solution in C,C++,Python | URI - BEECROWD - BEE 1096 Solution in C,C++,Python

                                                                                            beecrowd | 1096

Sequence IJ 2

Adapted by Neilor Tonin, URI  Brazil

                                                                                             Timelimit: 1

URI / BEE CROWD 1096 - Sequence IJ 2 Solution in C,C++,Python | URI - BEECROWD - BEE 1096 Solution in C,C++,Python:

Make a program that prints the sequence like the following example.

Input

This problem doesn't have input.

Output

Print the sequence like the example below.

Input Sample	Output Sample
	I=1 J=7 I=1 J=6 I=1 J=5 I=3 J=7 I=3 J=6 I=3 J=5 ... I=9 J=7 I=9 J=6 I=9 J=5

                                                          Demonstration:

This program does not take user inputs . Then check the conditions for each test case contains two integer number i and j .Then calculating the sequence by using conditional loop.

Start with i =1 and j =7 . For every iteration, increment i by 2 and decrement j by 1.

Finally print the result.

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

  URI / BEE 1096 Solution in C :   

URI / BEECROWD Online Judge 1096 Solve  in C :

#include <stdio.h>

int main()
{
    int I,J;
    for(I=1;I<=9;I=I+2)
    {
        for(J=7;J>=5;J--)
            printf ("I=%d J=%d\n",I,J);
    }
    return 0;
}

  URI / BEE 1096 Solution in C++ :   

URI / BEECROWD Online Judge 1096 Solve  in C++ :

#include <iostream>

using namespace std;

int main(){
    
    for(int i = 1; i < 10; i+=2){
            for(int j = 7; j > 4; j--){
                    cout << "I=" << i << " " << "J=" << j << "\n";
            }
    }
    return 0;
}

  URI / BEE 1096 Solution in Python :   

URI / BEECROWD Online Judge 1096 Solve  in Python :

for i in range(1,10,2):
    for j in range(7,4,-1):
        print(f"I={i} J={j}")

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